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- Thread starter avb203796
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- #2

mukundpa

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- #3

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but given just an angle how would I know the height?

- #4

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are you sure that's all the information you've been given?

- #5

mukundpa

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2. They may give the slant height and with that and the angle known we can calculate the vertical height.

Just check again the question otherwise it is not possible to caclculat the change in KE with given data.

- #6

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A 50.0 kg crate slides down a slope of 45 degrees for a distance of 200.0m. how much work will be done by gravity? How much work will be done by friction, if the kinetic coefficent of friction is 0.12? What speed will it attain at this point if it was originally at rest? By how much will its gravitaional potential energy change during the slide?

Again I have solve all of the problem except for the last question.

- #7

mukundpa

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the distance covered is given 200m

hence the vertical height fallen is 200 sin 45deg. = 2000*707 = 141.4 m.

now you can calculate mgh

remember the height is lost means the potential energy decreases(may be the answer is having a negative sign)

- #8

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How did you solve the question1?

Please show your method. I am asking avb - others don't reply.

Please show your method. I am asking avb - others don't reply.

- #9

mukundpa

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mgh is the loss in potential energy.(_ve)

- #10

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- #11

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Ok thank you mukundpa!

- #12

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- #13

mukundpa

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loss in potential energy = gain in KE + work done against friction

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