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## Homework Statement

[tex]f(x)[/tex]= -x-1,-4[tex]\leq[/tex] [tex]x[/tex] [tex]\leq[/tex]-1

......= x+1, -1[tex]\leq[/tex] [tex]x[/tex] [tex]\leq[/tex]0

......= -x+1, 0[tex]\leq[/tex] [tex]x[/tex] [tex]\leq[/tex]4

obtain the graph of [tex]g(x)=3f(1/2(x+2))-2[/tex] from the graph of [tex]f(x)[/tex]

## The Attempt at a Solution

i am not sure how to obtain the graph.

for example, should i plug in (1/2(x+2)) into -x-1, and have something like, -3(1/2(x+2))-2-1.

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